A piece of wood weights `40gxxg` in air. A piece of brass of mass 12 g is tied to the wooden piece and the combination floats just totally immersed in water. If the specific gravity of brass is 8.5, calculate the specific gravity of wood. [Density of water = `1g*cm^(-3)`]
Text Solution
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Let the density of the piece of wood be `rhog*cm^(-3)`. Total volume of the pieces of wood and brass = `(40/rho+12/8.5)cm^(3)` Volume of displaced water = `(40/rho+12/8.5)cm^(3)` By the condition, weight of the piece of wood + weight of the piece of brass = weight of water displaced by both of them or, `40+12=(40/rho+12/8.5)xx1or,52=40/rho+12/8.5` or, `40/rho=52-1.41or,rho=40/50.59=0.79` `therefore` Specific gravity of wood is 0.79.
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