The apparent weights of two bodies suspended from the two ends of a balance beam and immersed in water are the same. The mass and density of one body are 32g and `8g*cm^(-3)` respectively. If the density of the other body is `5g*cm^(-3)`, then find its mass.
Text Solution
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Let the mass of the second body be m g. Volume of the first body = `32/8=4cm^(3)` `therefore` Volume of water displaced by the first body = `4cm^(3)` Volume of the second body = `m/5cm^(3)` `therefore` Volume of water displaced by the second body = `m/5cm^(3)` By the problem, apparent weight of the first body = apparent weight of the second body `therefore` Real weight of the first body - weight of water displaced by the first body = real weight of the second body - weight of water displaced by the second body or, `32-4=m-m/5or,28=(4m)/5or,m=35` `therefore" "` Mass of the second body is 35 g.
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