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A glass ball of density 2.6g*cm^(-3) is ...

A glass ball of density `2.6g*cm^(-3)` is coated with a thick layer of wax of density `0.8g*cm^(-3)`. If the combination floats in water remaining completely submerged, find the ratio of the volume of wax to that of the glass ball.

Text Solution

Verified by Experts

Let volume of glass be `V_(1)cm^(3)` and volume of wax be `V_(2)cm^(3)`.
According to the problem,
weight of glass ball + weight of wax = weight of displaced water
or, `V_(1)xx2.6xxg+V_(2)xx0.8xxg=(V_(1)+V_(2))xx1xxg`
or, `V_(1)(2.6-1)=V_(2)(1-0.8)or,V_(2)/V_(1)=1.6/0.2=8/1`
`therefore` Volume of wax: volume of glass = 8 : 1.
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