A body can float on a liquid keeping `1/4`th of its volume outside the liquid. The body is completely immersed inside the liquid and then released. What will be its upward acceleration at that time?
Text Solution
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Let volume of the body be V and density be `rho` , density of the liquid be `rho.`. According to the condition of floatation, `Vxxrhoxxg=3/4Vxxrho.xxgor,rho.=(4rho)/3` When the body is completely immersed in the liquid, the net upward force = buoyant force - weight or, `Vrhoa=Vrho.g-Vrhog" "`[a = upward acceleration] or, `Vrhoa=V.(4)/(3)rho*g-Vrhog=1/3Vrhog` or, `a=1/3g`.
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