A body of uniform cross-section remains floating in a liquid. The density of the liquid is 3 times that of the body. What part of that body remains outside the liquid?
Text Solution
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Let the volume of the body be V, density be `rho` and density of the liquid be `3rho`. Let us assume that x part of the body remains immersed in the liquid. So, according to the condition of floatation, weight of the body = weight of displaced liquid or, `Vrhog=Vx*3rho*gor,x=1/3` `therefore(1-1/3)or2/3` part of the body remains outside the liquid.
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