A piece of silver weighing 105 gf and another piece of glass weighing 130 gf are placed on the right and left pan of a balance respectively. Which pan will move down when the balance is immersed in water? [Given, the density of silver, `rho_(1)=10.5g*cm^(-3)` and density of glass, `rho_(2)=2.6g*cm^(-3)`]
Text Solution
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Here weight of the piece of silver, `W_(1)=105` gf and weight of the piece of glass, `W_(2) = 130` gf. Now, volume of the piece of silver, `V_(1)=105/rho_(1)=105/10.5=10cm^(3)` and volume of the piece of glass, `V_(2)=130/rho_(2)=130/2.6=150cm^(3)` Since density of water is `1g*cm^(-3)`, weight of the water displaced by the pieces of silver and glass will be 10 gf and 50 gf respectively. Therefore on immersing the blance in water, the apparent weight of the piece of silver, `W._(1)=W_(1)-10=105-10=95`gf and the apparent weight of the piece of glass, `W._(2)=W_(2)-50=130-50=80`gf SInce `W._(2)ltW._(1)`, the right pan i.e. the pan having piece of silver on it, will move down.
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