Tangent are drawn to the circle `x^2+y^2=1` at the points where it is met by the circles `x^2+y^2-(lambda+6)x+(8-2lambda)y-3=0,lambda` being the variable. The locus of the point of intersection of these tangents is `2x-y+10=0` (b) `2x+y-10=0` `x-2y+10=0` (d) `2x+y-10=0`

Explanation

To solve the problem, we need to find the locus of the point of intersection of the tangents drawn to the circle \(x^2 + y^2 = 1\) at the points where it intersects with the given circle \(x^2 + y^2 - (\lambda + 6)x + (8 - 2\lambda)y - 3 = 0\).

### Step 1: Identify the circles
The first circle is given by:
\[ x^2 + y^2 = 1 \]
The second circle is given by:
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