If in the expansion of `2x+5^(10)` , the numerically greatest tem in equal to the middle term, then find the values of `xdot`

Answer

`x in (-3,-25/12) uu (25/12,3)`

Explanation

In the expansion of `(2x+5)^(10)`, the middle term is `T_(6)` .
Consider the expansion of `(1+2x//5)^(10)` .Now
`|(T_(6))/(T_(5))|gt1` and `|(T_(7))/(T_(6))|lt 1`
`rArr |(10-5+1)/(5)(2x)/(5)|gt1` nd `|(10-6+1)/(6)(2x)/(5)|lt1`
`rArr |(12)/(25)x|gt1` and `|(x)/(3)|lt1`
`rArr (25)/(12)lt|x|lt3`
`rArrx in (-3,-25/12)uu(25/1,3)`