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Let veca , vecb , vecc be unit vectors ...

Let ` veca , vecb , vecc` be unit vectors such that ` veca .vecb =0=veca.vecc` . If the angle between `vecb and vecc " is " pi/6 , " then " veca ` equals

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We have `veca.vecb = veca .vecb =0`
This implies that `veca` is perpenedicular to both `vecb and vecc`. Thus, `veca` is a unit vector, perpendicular to both `vecb and vecc`.Hence,
`vecr = +-(vecb xx vecc)/(|vecbxxvecc|) = +-(vecbxxvecc)/(|vecb||vecc|sinpi//3)`
` = +- 2 (vecb xx vecc)`
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