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If a(vecalphaxxvecbeta)=b(vecbetaxxvecga...

If `a(vecalphaxxvecbeta)=b(vecbetaxxvecgamma)+c(vecgammaxxvecalpha)=vec0` and at least one of a,b and c is non zero then vectors `vecalpha, vecbeta, vecgamma` are (A) parallel (B) coplanar (C) mutually perpendicular (D) none of these

A

parallel

B

coplanar

C

mutually perpendicular

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
b
Taking dot product of `a (vecalpha xx vecbeta) + b(vecbeta xx vecgamma) + c(vecgamma xx vecalpha) = 0 " with " vecgamma , vecalpha and vec beta` respectively.
we have
` a [vecalpha vecbeta vecgamma] =0`
`b [ vecalpha vecbeta vecgamma] =0`
`c[vecalpha vecbeta vecgamma] =0`
since at least one of a,b and c `ne 0`. we have
` [vecalpha vecbeta vecgamma ]= 0`
Hence `vecalpha, vecgamma , and vecgamma ` are coplanar.
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