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The scalar vecA.(vecB+vecC)xx(vecA+vecB+...

The scalar `vecA.(vecB+vecC)xx(vecA+vecB+vecC)` equals (A) 0 (B) `[vecA vecB vecC]+[vecB vecC vecA]` (C) `[vecA vecB vecC]` (D) none of these

A

0

B

`[vecA vecB vecC]+ [vecB vecC vecA] `

C

`[vecA vecB vecC]`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
a
`vecA.(vecB + vecC) xx (vecA + vecB +vecC)`
` vecA . ([vecB xx vecA +vecB xx vecB + vecC + vecC xx vecA + vecC xx vecB +vecC xx vecC]`
`= vecA.vecBxxvecA + vecA.vecBxxvecC+vecA.vecCxx vecA + vecA+ vecC xx vecB " " ( "using" veca xx veca =0)`
`0+[vecA vecB vecC]+0+ [vecA vecC vecB]`
`[vecA vecB vecC]-[vecA vecB vecC]`
=0
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Knowledge Check

  • The value of veca.(vecb+vecc)xx(veca+vecb+vecc) , is

    A
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    B
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    C
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    None of these

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    A
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