If `veca=2hati + hatj + hatk,vecb=hati + 2hatj + 2hatk ,vecc= hati + hatj + 2hatk and [vecavecbveci] hati+ [vecavecb vecj] hatj+ [veca vecb hatk] k` is equal to

Answer

b

Explanation

Let `veca xx vecb = x hati + y hatj + zhatk`. Therefore,
,` [veca vecb hati] = (veca xx vecb) . Hati =x`
`[veca vecb hatj] = (veca xx vecb ) . Hatj = y `
`[veca vecb veck] = (veca xx vecb) . Hatk =z`
Hence, ` [ veca vecb hati] hati + [ veca vecb hatj] hatj`
` [ veca vecb hatk] hatk = xhati = yhatj + zhatk + veca xx vecb `