If vectors `vecA=2hati+3hatj+4hatk, vecB=hati+hatj+5hatk and vecC` form a left handed system then `vecC` is (A) `11hati-6hatj-hatk` (B) `-11hati+6hatj+hatk` (C) `-11hati+6hatj-hatk` (D) `-11hati+6hatj-hatk`

Options

A. `11 hati - 6 hatj - hatk`
B. `-11 hati - 6 hatj - hatk`
C. `-11 hati - 6 hatj + hatk`
D. `-11 hati + 6 hatj - hatk`

Answer

b,d

Explanation

For `vecA, vecB and vecC` to form a left- handed system
`[vecA vecB vecC] lt 0`
`vecA xx vecV=|{:(hati,hatj,hatk),(2,3,4),(1,1,5):}|=11hati -6hatj-hatk`
(i) is satisfied by options (b) and (d)