If `veca,vecb, vecc` are unit coplanar vectors then the scalar triple product `[2veca-vecb 2vecb-c vec2c-veca]` is equal to (A) `0` (B) `1` (C) `-sqrt(3)` (D) `sqrt(3)`

Options

A. 0
B. 1
C. `-sqrt3`
D. `sqrt3`

Answer

a

Explanation

`veca vecb and vecc` are unit coplanar vectors, `2veca- vecb , 2vecb - 2vecc and 2vecc - veca` are also coplanar, vectors ], being a linear combination of `veca , vecb and vecc` thus ` [ 2 veca - vecb 2vecb - vecc 2vecc - veca] =0`