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A ball reaches a racket at 60m//s along ...

A ball reaches a racket at `60m//s` along +X dirction and leaves the racket in the opposite direaction with the same speed. Assuming that the mass of the ball as `50gm` and the contact time is `0.02` second the force exerted by the racket on the ball is .

A

300 N along `+` X direction

B

300 N along`-` X direction

C

3,00,000 N along `+` X direction

D

3,00,000 N along`-`X direction

Text Solution

Verified by Experts

The correct Answer is:
B
`F_("avg")=ma, a=(v-u)/(t)`
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