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A person of mass 60 kg is in a lift. The...

A person of mass 60 kg is in a lift. The change in the apparent weight of the person, when the lift moves up with an acceleration of `2ms^(-2)` and then down with an acceleration of `2ms^(-2)` is `("take g = "10 m//sec^(2))`

A

120 N

B

240 N

C

480 N

D

720 N

Text Solution

Verified by Experts

The correct Answer is:
C
`w_(1)=m(g+a), w_(2)=m(g-a)`
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