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The block is placed on a frictionless su...

The block is placed on a frictionless surface in gravity free space. A heavy string of a mass m is connected and force F is applied on the string, then the tension at the middle of rope is

A

`(((m)/(2)+M).F)/(m+M)`

B

`(((M)/(2)+m).F)/(m+M)`

C

zero

D

`(M.F)/(m+M)`

Text Solution

Verified by Experts

The correct Answer is:
A

`F=ma, a=(F)/(M+m), T=((m)/(2)+M)a`
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Knowledge Check

  • The block is placed on a frictionless surface in gravity free space. A heavy string of a mass m is conncected and force F is applied on the string then the tension at the middle of rope is .

    A
    `(((m)/(2)+M).F)/(m+M)`
    B
    `(((M)/(2)+m).F)/(m+M)`
    C
    zero
    D
    `(M.F)/(m+M)`
  • A block of mass M is pulled along a horizontal frictionless surface by a rope of mass m. If a force F is applied at one end of the rope, the force which the rope exerts on the block is :

    A
    `F//(M+m)`
    B
    F
    C
    `FM(m+M)`
    D
    0
  • A block of mass M is pulled along a horizontal frictionless surface by a rope of mass m. If a force P is applied at the free end of the rope, the force exerted by the rope on the block is

    A
    (a) `(Pm)/(M+m)`
    B
    (b) `(Pm)/(M-m)`
    C
    (c) P
    D
    (d) `(PM)/(M+m)`
  • NARAYNA-LAW OF MOTION-EXERCISE - II (C.W)(OBJECTS SUSPENDED BY STRINGS AND APPARENT WEIGHT)
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