A particle of mass m, initially at rest ...

A particle of mass m, initially at rest is acted upon by a variable force F for a brief interval of time T. It begins to move with a velocity u after the force stops acting. F is shown in the graph as a function of time. The curve is a semicircle. Then

`u=(piF_(0)^(2))/(2m)`

`u=(piT^(2))/(8m)`

`u=(piF_(0)T)/(4m)`

`u=(piF_(0)T)/(2m)`

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The correct Answer is:

Impulse = Area of semi circle

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A particle of mass m at rest is acted upon by a force F for a time t. Its Kinetic energy after an interval t is

`(F^(2)t^(2))/(m)`

`(F^(2)t^(2))/(2m)`

`(F^(2)t^(2))/(3m)`

`(Ft)/(2m)`

2 Ftm

`(2Ft)/(m)`

`(Ft)/(m)`

`(F^2t^2)/(2m)`

`(F^2t^2)/(m)`

`(F^2t^2)/(2m)`

`(F^2t^2)/(3m)`

`(Ft)/(2m)`