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A particle of mass m, initially at rest ...

A particle of mass m, initially at rest is acted upon by a variable force F for a brief interval of time T. It begins to move with a velocity u after the force stops acting. F is shown in the graph as a function of time. The curve is a semicircle. Then

A

`u=(piF_(0)^(2))/(2m)`

B

`u=(piT^(2))/(8m)`

C

`u=(piF_(0)T)/(4m)`

D

`u=(piF_(0)T)/(2m)`

Text Solution

Verified by Experts

The correct Answer is:
C
Impulse = Area of semi circle
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Knowledge Check

  • A particle of mass m at rest is acted upon by a force F for a time t. Its Kinetic energy after an interval t is

    A
    `(F^(2)t^(2))/(m)`
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    2 Ftm
    B
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    D
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  • A particle of mass mat rest is acted upon by a force F for a time t. Its kinetic energy after an interval t is:

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