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A block is kept on a frictionless inclin...

A block is kept on a frictionless inclined surface with angle of inclination `alpha`. The incline is given an acceleration ‘a’ to keep the block stationary. Then 'a' is equal to

A

`(g)/(tan alpha)`

B

`g "cosec "alpha`

C

g

D

`g tan alpha`

Text Solution

Verified by Experts

The correct Answer is:
D

`ma cos alpha=mg sin alpha`
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NARAYNA-LAW OF MOTION-EXERCISE - II (C.W)(OBJECTS SUSPENDED BY STRINGS AND APPARENT WEIGHT)
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