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Two identical blocks each of mass ''M'' ...

Two identical blocks each of mass ''M'' are tied to the ends of a string and the string is laid over a smooth fixed pulley. Initially the masses are held at rest at the same level. What fraction of mass must be removed from one block and added to the other, so that it has an acceleration of `1//5^("th")` of the acceleration due to gravity

A

`1//10`

B

`2.1/5`

C

`3.2/5`

D

`4.1/20`

Text Solution

Verified by Experts

The correct Answer is:
B

`F=ma, a=((m_(1)-m_(2))/(m_(1)+m_(2)))g`
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NARAYNA-LAW OF MOTION-EXERCISE - II (C.W)(OBJECTS SUSPENDED BY STRINGS AND APPARENT WEIGHT)
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