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A body is released from the top of a smo...

A body is released from the top of a smooth inclined plane of inclination `theta`. It reaches the bottom with velocity v. If the angle of inclination is doubled for the same length of the plane, what will be the velocity of the body on reaching the ground

A

v

B

2v

C

`(2cos theta)^((1)/(2))v`

D

`(2 sin theta)^((1)/(2))v`

Text Solution

Verified by Experts

The correct Answer is:
C
`v=sqrt(2gl sin theta), v^(1)=sqrt(2gl sin 2 theta)`
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