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A 30 kg box has to move up an inclined p...

A 30 kg box has to move up an inclined plane of slope `30^(@)` to the horizontal with a uniform velocity of `5 ms^(-1)`.If the frictional force retarding the motion is 15ON, the horizontal force required to move the box up is`(g=10ms^(-2))`

A

`300xx(2)/(sqrt3)N`

B

`300xx(sqrt3)/(2)N`

C

`300N`

D

`150N`

Text Solution

Verified by Experts

The correct Answer is:
A
`F cos theta=mg sin theta +f, f=mu_(s)N`
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