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The angular displacement of a particle i...

The angular displacement of a particle is given by `theta = t^3 + 2t +1`, where `t` is time in seconds. Its angular acceleration at `t=2s` is

A

14 rad `s^(-2)`

B

17 rad`s^(-2)`

C

12 rad`s^(-2)`

D

9 rad`s^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
C
`alpha = (d^(2)theta)/(dt^(2))`
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