A photoelectron is moving with a maximum...

A photoelectron is moving with a maximum velocity of `10^(6) m//s`. Given `e=1.6xx10^(-19) c`, and `m=9.1xx10^(-31) kg`, the stopping potential is

A

2.5 V

B

2.8 V

C

2.0 V

D

1.4 V

Text Solution

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`(1)/(2)mv^(2)=eV_(0)`

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