Home
Class 12
MATHS
int(cos2x-cos2alpha)/(cosx-cosalpha)dx...

`int(cos2x-cos2alpha)/(cosx-cosalpha)dx`

Text Solution

Verified by Experts

The correct Answer is:
`sinx+x"cos"theta+C`
`int(cos2x-cos2theta)/(cosx-costheta)dx=int(cos^(2)x-cos^(2)theta)/(cosx-"cos"theta)dx`
`=int(cosx+"cos"theta)dx`
`=sinx+x"cos"theta+C`
Promotional Banner

Topper's Solved these Questions

  • INDEFINITE INTEGRATION

    CENGAGE|Exercise Exercise 7.2|7 Videos

  • INDEFINITE INTEGRATION

    CENGAGE|Exercise Exercise 7.3|16 Videos

  • INDEFINITE INTEGRATION

    CENGAGE|Exercise Question Bank|25 Videos

  • HYPERBOLA

    CENGAGE|Exercise JEE Advanced Previous Year|14 Videos

  • INEQUALITIES AND MODULUS

    CENGAGE|Exercise Single correct Answer|21 Videos

Similar Questions

Explore conceptually related problems

int(cos2x-cos2 alpha)/(cos x-cos alpha)dx

Evaluate: int(cos2x-cos2 alpha)/(cos x-cos alpha)dx

Evaluate: int(cos2x-cos2 alpha)/(cos x-cos alpha)dx

int(cos2x-cos2 alpha)/(sin x-sin alpha)dx=

Evaluate int ((cosx - 2cos 2alpha)/(cosx - cos alpha)) dx .

If I=int(cos2x-cos2alpha)/(sin a - sinalpha)dx ,then I equals

int ((cos 2x - cos 2 alpha))/((cosx -cos alpha)) dx = ?

int(cos3x-cos2x)/(cos x)dx

int(cos alpha)/(sin x cos(x-alpha))dx=

int(cos(x+alpha))/cosx dx=