Home
Class 11
PHYSICS
A particle moves in a straight line with...

A particle moves in a straight line with a uniform acceleration a. Initial velocity of the particle is zero. Find the average velocity of the particle in first 's' distance.

Text Solution

Verified by Experts

`because s = (1)/(2) at^(2) " " therefore (s^(2))/(t^(2))= (1)/(2)` as `" " ` Average velocity `= (s)/(t) = sqrt(("as")/(2))`
Promotional Banner

Topper's Solved these Questions

  • KINEMATICS (MOTION ALONG A STRAIGHT LINE AND MOTION IN A PLANE)

    ALLEN|Exercise BEGINNER S BOX-1|6 Videos
  • KINEMATICS (MOTION ALONG A STRAIGHT LINE AND MOTION IN A PLANE)

    ALLEN|Exercise BEGINNER S BOX-2|7 Videos
  • KINEMATICS

    ALLEN|Exercise Integer Type Question|3 Videos
  • MISCELLANEOUS

    ALLEN|Exercise SUBJECTIVE QUESTION|9 Videos

Similar Questions

Explore conceptually related problems

A particle moves on a straight line with a uniform velocity. The angular momentum of the particles is

The acceleration-displacement graph of a particle moving in a straight line is as shown in figure, initial velocity of particle is zero. Find the velocity of the particle when displacement of the particle is s=12 m .

Acceleration (a) -displacement (s) graph of a particle moving in a straight line is as shown in the figure. The initial velocity of the particle is zero. The v-s graph of the particle would be

Acceleration (a)-displacement(s) graph of a particle moving in a straight line is shown here. The initial velocity of the particle is zero. The v-s graph of the particle would be

Acceleration of two identical particles moving in a straight line are as shown in figure. If initial velocity of both the particles was zero. Then velocity of their centre of mass after 10 s will be

Acceleration v/s displacement graph of a particle moving in a straight line is as shown in the figure. The initial velocity of the particle is zero. The velocity v/s displacement graph of the particle would be :

Acceleration-time graph of a particle moving in a straight line is as shown in figure. At time t = 0, velocity of the particle is zero. Find (a) average acceleration in a time interval from t = 6 s to t = 12 s, (b) velocity of the particle at t = 14 s.

Statement-I : A particle moves in a straight line with constant acceleration. The average velocity of this particle cannot be zero in any time interval. Statement-II : For a particle moving in straight line with constant acceleration, the average velocity in a time interval is (u+v)/(2) , where u and v are initial and final velocity of the particle of the given time interval.