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A juggler throws ball into air. He throu...

A juggler throws ball into air. He throus one whenever the previus one is at its highest point. How high do the balls rise if he throus (n) balls each second. Acceleration the to gravity=g`.

Text Solution

Verified by Experts

Juggler throws n balls in one second so time interval between two consecutive throws is `t = (1)/(n)s ` each ball takes `(1)/(n) s` to reach maximum height
So `h_(max)= (1)/(2) xx "gt"^(2) = (1)/(2) xx g ((1)/(n))^(2)`
`h_(max)= (g)/(2n^(2))`
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