Home
Class 11
PHYSICS
A particle is projected from the ground ...

A particle is projected from the ground at an angle such that it just clears the top of a polar after `t_1` time its path. It takes further `t_2` time to reach the ground. What is the height of the pole ?

Text Solution

Verified by Experts

Height of the pole is equal to the vertical displacement of the particle at time `t_1`
Vertical displacement `y= ut_1 + (1)/(2) a t_(1)^(2) = ut_1 - (1)/(2) "gt"_(1)^(2)………….` (i)
and total flight time `t_1 + t_2 = ( 2u_2)/(g) rArr u_1 = (g)/(2) (t_1 +t_2)`
put value `u_2` in equation (i) `y = (g)/(2)(t_1 + t_2) t_1 - (1)/(2) g(t_1)^(2) = (1)/(2)"gt"_1 t_2`. so height of the pole `= (1)/(2) "gt"_1t_2`.
Promotional Banner

Topper's Solved these Questions

  • KINEMATICS (MOTION ALONG A STRAIGHT LINE AND MOTION IN A PLANE)

    ALLEN|Exercise BEGINNER S BOX-1|6 Videos

  • KINEMATICS (MOTION ALONG A STRAIGHT LINE AND MOTION IN A PLANE)

    ALLEN|Exercise BEGINNER S BOX-2|7 Videos

  • KINEMATICS

    ALLEN|Exercise Integer Type Question|3 Videos

  • MISCELLANEOUS

    ALLEN|Exercise SUBJECTIVE QUESTION|9 Videos

Similar Questions

Explore conceptually related problems

A ball is released from the top of a tower of height h metre. It takes T second to reach the ground. What is the position of the ball in T/3 second?

A particle is projected from ground with velocity 40sqrt2m at 45^(@) .At time t=2s

A particle is projected vertically upwards from a point A on the ground. It takes t_(1) time to reach a point B but it still continues to move up. If it takes further t_(2) time to reach the ground from point B then height of point B from the ground is :-

A body is released from the top of a tower of height h. It takes t sec to reach the ground. Where will be the ball after time (t)/(2) sec?

A particle is projected from the ground at t = 0 so that on its way it just clears two vertical walls of equal height on the ground. The particle was projected with initial velocity u and at angle theta with the horiozontal. If the particle passes just grazing top of the wall at time t = t_1 and t = t_2 , then calculate. (a) the height of the wall. (b) the time t_1 and t_2 in terms of height of the wall. Write the expression for calculating the range of this projectile and separation between the walls.

A particle is projected from ground with velocity 40sqrt(2)m//s at 45^(@) . At time t=2s

A stone projected vertically up from the ground reaches a height y in its path at t_(1) seconds and after further t_(2) seconds reaches the ground. The height y is equal to