A particle starts from the rest, moves with constant acceleration for 15s. If it covers `s_1` distance in first 5s then distance `s_2` in next 10s, then find the relation between `s_1 & s_2`.

Explanation

To solve the problem, we will use the equations of motion under constant acceleration. Let's break it down step by step.

### Step 1: Understand the given information
The particle starts from rest, which means its initial velocity \( u = 0 \). It moves with a constant acceleration \( a \) for a total time of \( 15 \) seconds. We need to find the distances \( s_1 \) and \( s_2 \) covered in the first \( 5 \) seconds and the next \( 10 \) seconds, respectively.

### Step 2: Calculate \( s_1 \) (distance covered in the first 5 seconds)
Using the equation of motion:
\[
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