A particle starts from the rest, moves w...

A particle starts from the rest, moves with constant acceleration for 15s. If it covers `s_1` distance in first 5s then distance `s_2` in next 10s, then find the relation between `s_1 & s_2`.

Text Solution

AI Generated Solution

To solve the problem, we will use the equations of motion under constant acceleration. Let's break it down step by step. ### Step 1: Understand the given information The particle starts from rest, which means its initial velocity \( u = 0 \). It moves with a constant acceleration \( a \) for a total time of \( 15 \) seconds. We need to find the distances \( s_1 \) and \( s_2 \) covered in the first \( 5 \) seconds and the next \( 10 \) seconds, respectively. ### Step 2: Calculate \( s_1 \) (distance covered in the first 5 seconds) Using the equation of motion: \[ ...

Topper's Solved these Questions

KINEMATICS (MOTION ALONG A STRAIGHT LINE AND MOTION IN A PLANE)
ALLEN|Exercise BEGINNER S BOX-5|5 Videos
KINEMATICS (MOTION ALONG A STRAIGHT LINE AND MOTION IN A PLANE)
ALLEN|Exercise BEGINNER S BOX-6|9 Videos
KINEMATICS (MOTION ALONG A STRAIGHT LINE AND MOTION IN A PLANE)
ALLEN|Exercise BEGINNER S BOX-3|2 Videos
KINEMATICS
ALLEN|Exercise Integer Type Question|3 Videos
MISCELLANEOUS
ALLEN|Exercise SUBJECTIVE QUESTION|9 Videos

A body starts from rest and moves with constant acceleration for t s. It travels a distance x_1 in first half of time and x_2 in next half of time, then

`x_2 = 3x_1`

`x_2 = x_1`

`x_2 = 4x_1`

`x_2 = 2x_1`

A particle experiences constant acceleration for 20 s after starting from rest. If it travels a distance S_1 in the first 10 s and distance S_2 in the next 10 s, the relation between S_1 and S_2 is :

`S_2 = 3S_1`

`S_1 = 3S_2`

`S_2 = 2S_1`

`S_1 = 10S_2`

A body travels for 15 s starting from rest with a constant acceleration. If it travels distances x,y and z in the first 5 s , second 5 s and the next 5 s, repectively, the ralation between x,y and z is

`x=y=z`

`5x=3y=z`

`x=y/3=z/5`

`x=y/5=z/3`