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A container of volume V, contains 0*28 g...

A container of volume V, contains `0*28` g of `N_(2)` gas. If same volume of an unknown gas under similar conditions of temperature and pressure weighs `0*44` g, the molecular mass of the gas is

A

22

B

44

C

66

D

88

Text Solution

Verified by Experts

The correct Answer is:
B
acc to Avogadro.s law
`""^(n)N_(2)=""^(n)x`
`(0.28)/(28)=(0.44)/(M_(x))`
`therefore M_(x)=44`
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