The molarity of 0.6N phosphorous acid is

Options

A. 0.3
B. 0.1
C. 0.9
D. 0.6

Explanation

To find the molarity of 0.6N phosphorous acid (H₃PO₃), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Given Information:**
- Normality (N) of phosphorous acid = 0.6N
- Phosphorous acid is represented by the formula H₃PO₃.

2. **Determine the n-factor:**
- Phosphorous acid (H₃PO₃) is a dibasic acid, meaning it can donate two protons (H⁺ ions) in a reaction.
- Therefore, the n-factor for phosphorous acid is 2.

3. **Use the Relationship Between Normality and Molarity:**
- The relationship between normality (N) and molarity (M) is given by the formula:
\[ \text{Normality} = n \times \text{Molarity} \]
- Rearranging this formula to find molarity gives:
\[ \text{Molarity} = \frac{\text{Normality}}{n} \]

4. **Substitute the Values:**
- Now substitute the known values into the rearranged formula:
\[ \text{Molarity} = \frac{0.6N}{2} = 0.3M \]

5. **Conclusion:**
- The molarity of 0.6N phosphorous acid is 0.3M.

### Final Answer:
The molarity of 0.6N phosphorous acid is **0.3M**.

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