Home
Class 11
CHEMISTRY
The percentage of C, H and N in an orga...

The percentage of C, H and N in an organic compound are 40% , 13.3% and 46.7% respectively then empirical formula is

A

`C_(3)H_(13)N_(3)`

B

`CH_(2)N`

C

`CH_(4)N`

D

`CH_(6)N`

Text Solution

Verified by Experts

The correct Answer is:
C
`ul("Element % composition At.Wt R.N.A S.R")`
`{:(C,40,12,=(40)/(12)=3.33,(3.33)/(3.33)=1),(H,13.3,1,(13.3)/(1)=13.3,(13.3)/(3.33)=4),(N,46.7,14,(46.7)/(14)=3.33,(3.33)/(3.33)=1):}`
`thereforeE.F=CH_(4)N`
Promotional Banner

Topper's Solved these Questions

  • SOME BASIC CONCEPTS OF CHEMISTRY

    NARAYNA|Exercise EXERCISE - I (H.W)(NUMERICAL CALCULATIONS BASED ON CHEMICAL EQUATIONS)|19 Videos

  • SOME BASIC CONCEPTS OF CHEMISTRY

    NARAYNA|Exercise EXERCISE - I (H.W)(METHODS OF EXPRESSING CONCENTRATIONS)|9 Videos

  • SOME BASIC CONCEPTS OF CHEMISTRY

    NARAYNA|Exercise EXERCISE - I (H.W)(EQUIVALENT WEIGHT)|3 Videos

  • SOME BASIC CONCEPTS IN CHEMISTRY STOICHIOMETRY (PART-I)

    NARAYNA|Exercise All Questions|555 Videos

  • SOME BASIC PRINCIPLES AND TECHNIQUES

    NARAYNA|Exercise EXERCISE -IV (QUALITATIVE AND QUANTITATIVE ANALYSIS OF ORGANIC OF COMPOUNDS)|8 Videos

Similar Questions

Explore conceptually related problems

An organic compound with C =40 % and H= 6.7% will have the empirical formula

An organic compound with C =40 % and H= 6.7% will have the empirical formula

An organic compound containes C=74.0%, H=8.65% and N=17.3% . Its empirical formul ais

An organic compound with C =40 % and H= 13.33 % and N=46.67 % Its empirical empirical formula would be

An organic compound contains C = 40%, H = 13.33% , and N = 46.67% . Its empirical formula will be

An organic compound containing C,H and N have the percentage 40,13.33 and 46.67 respectively. Its empirical formula may be :

In an organic compound, C=68.5% and H=4.91% . Which empirical formula is correct for it ?