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Vapour density of a metal chloride is 66...

Vapour density of a metal chloride is 66. Its oxide contains `53%` metal. The atomic weight of the metal is

A

21

B

54

C

27.06

D

2.086

Text Solution

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The correct Answer is:
To find the atomic weight of the metal, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Given Information:** - Vapor density of the metal chloride (VD) = 66 - Percentage of metal in the oxide = 53% 2. **Assume the Weight of the Metal Oxide:** - Let the weight of the metal oxide be 100 grams. 3. **Calculate the Weight of the Metal:** - Weight of metal = 53% of 100 g = \( \frac{53}{100} \times 100 = 53 \) g 4. **Calculate the Weight of Oxygen:** - Weight of oxygen = Total weight of oxide - Weight of metal - Weight of oxygen = \( 100 - 53 = 47 \) g 5. **Calculate the Equivalent Weight of the Metal Oxide:** - The equivalent weight of an oxide can be calculated using the formula: \[ \text{Equivalent Weight of Oxide} = \frac{\text{Molar Mass of Oxide}}{\text{Valence Factor}} \] - For \( O^{2-} \), the valence factor = 2. - The atomic weight of oxygen = 16 g/mol, so for \( O_2 \): \[ \text{Equivalent Weight of O} = \frac{16}{2} = 8 \, \text{g/equiv} \] 6. **Calculate the Equivalent Weight of the Metal:** - Using the formula for equivalent weight: \[ \text{Equivalent Weight of Metal} = \frac{\text{Weight of Metal}}{\text{Weight of Oxygen}} \times \text{Equivalent Weight of Oxide} \] - Substitute the values: \[ \text{Equivalent Weight of Metal} = \frac{53}{47} \times 8 \] - Calculate this: \[ \text{Equivalent Weight of Metal} = \frac{424}{47} \approx 9.02 \, \text{g/equiv} \] 7. **Calculate the Equivalent Weight of Chloride:** - The equivalent weight of chloride \( Cl^- \) is calculated as: \[ \text{Equivalent Weight of Cl} = \frac{35.5}{1} = 35.5 \, \text{g/equiv} \] 8. **Use the Vapor Density to Find Valency:** - The formula relating valency, vapor density, and equivalent weights is: \[ \text{Valency} = \frac{2 \times \text{Vapor Density}}{\text{Equivalent Weight of Metal} + \text{Equivalent Weight of Chloride}} \] - Substitute the known values: \[ \text{Valency} = \frac{2 \times 66}{9.02 + 35.5} \] - Calculate this: \[ \text{Valency} = \frac{132}{44.52} \approx 2.96 \approx 3 \] 9. **Calculate the Atomic Weight of the Metal:** - The atomic weight of the metal can be calculated using: \[ \text{Atomic Weight} = \text{Equivalent Weight} \times \text{Valency} \] - Substitute the values: \[ \text{Atomic Weight} = 9.02 \times 3 \approx 27.06 \] ### Final Answer: The atomic weight of the metal is approximately **27.06 g/mol**.

To find the atomic weight of the metal, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Given Information:** - Vapor density of the metal chloride (VD) = 66 - Percentage of metal in the oxide = 53% ...
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