The relative number of atoms of different elements in a compound are as follows : `A=1.33, B=1 and C=1.5`. The emperical formula of the compound is

Options

A. `A_(2)B_(2)C_(3)`
B. `ABC`
C. `A_(8)B_(6)C_(9)`
D. `A_(3)B_(3)C_(4)`

Explanation

To find the empirical formula of the compound given the relative number of atoms of different elements (A, B, and C), we can follow these steps:

### Step 1: Identify the relative number of atoms
We have:
- A = 1.33
- B = 1
- C = 1.5

### Step 2: Find the smallest value among the relative numbers
The smallest value among the given numbers is for element B, which is 1.

### Step 3: Divide each relative number by the smallest value
Now we will divide each of the relative numbers by the smallest value (1):
- For A: \( \frac{1.33}{1} = 1.33 \)
- For B: \( \frac{1}{1} = 1 \)
- For C: \( \frac{1.5}{1} = 1.5 \)

### Step 4: Convert to whole numbers
To convert these ratios into whole numbers, we can multiply each by a common factor. We will try multiplying by 6, as it seems to bring the values closer to whole numbers:
- For A: \( 1.33 \times 6 = 7.98 \) (approximately 8)
- For B: \( 1 \times 6 = 6 \)
- For C: \( 1.5 \times 6 = 9 \)

### Step 5: Write the empirical formula
Now we can express the empirical formula using the whole numbers obtained:
- A: 8
- B: 6
- C: 9

Thus, the empirical formula of the compound is \( A_8B_6C_9 \).

### Final Answer:
The empirical formula of the compound is \( A_8B_6C_9 \).

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