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Complete combustion of 0.858 g of compou...

Complete combustion of 0.858 g of compound X gives 2.63 g of `CO_(2)` and 1.28 g of` H_(2)`O. The lowest molecular mass X can have

A

172

B

129

C

86

D

43

Text Solution

Verified by Experts

The correct Answer is:
D
`"% of carbon "=(12)/(44)xx(2.63)/(0.858)xx100=83.6`
`"% of hydrogen "=(2)/(18)xx(1.28)/(0.858)xx100=16.4`
`therefore" Empirical formula "=C_(3)H_(7)`
M.wt = 43
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