Home
Class 11
CHEMISTRY
Mole fraction of C(3)H(5)(OH)(3) in a so...

Mole fraction of `C_(3)H_(5)(OH)_(3)` in a solution of 36 g of water and 46 g of glycerine is :

A

0.46

B

0.36

C

`0.20`

D

`0.40`

Text Solution

Verified by Experts

The correct Answer is:
C
`?_(s)=(n_(s))/(n_(s)+n_(o))`
Promotional Banner

Topper's Solved these Questions

  • SOME BASIC CONCEPTS OF CHEMISTRY

    NARAYNA|Exercise EXERCISE - II (H.W)(LAWS OF CHEMICAL COMBINATIONS)|14 Videos

  • SOME BASIC CONCEPTS OF CHEMISTRY

    NARAYNA|Exercise EXERCISE - II (H.W)(MOLE CONCEPT ATOMIC MASS, MOLECULAR MASS, AVOGADRO NUMBER)|8 Videos

  • SOME BASIC CONCEPTS OF CHEMISTRY

    NARAYNA|Exercise EXERCISE - II (C.W)(NUMERICAL CALCULATIONS BASED ON CHEMICAL EQUATIONS)|12 Videos

  • SOME BASIC CONCEPTS IN CHEMISTRY STOICHIOMETRY (PART-I)

    NARAYNA|Exercise All Questions|555 Videos

  • SOME BASIC PRINCIPLES AND TECHNIQUES

    NARAYNA|Exercise EXERCISE -IV (QUALITATIVE AND QUANTITATIVE ANALYSIS OF ORGANIC OF COMPOUNDS)|8 Videos

Similar Questions

Explore conceptually related problems

Mole fraction of C_(3)H_(5)(OH)_(3) in a solution of 36g of water and 46g of glycerine is:

Calculate the mole fraction of C_(3)H_(5)(OH)_(3) in a solution of 36 g of water and 46 g of glycerine.

In a binary solution, the component present in smaller proportion is called solute while the one in excess is known as solvent. The solution containing 1 mole of the solute in 1L of solution is known as one molar solution while the solution in which 1 mole of solute is dissolved in 1 kg of the solvent is called one molal solution. The ratio of the no. of moles of a particular component to the total no. of moles in the solution is known as its mole fraciton The mole fraction of glycerine C_(3)H_(5)(OH)_(3) in a solution containing 36 g of water and 46 g of glycerine is :

Mole fraction of glycerine (mol,wt=92)" in a solution containing 36g of H_(2)O and 46g of glycerine is "

How many moles are 3.6 g of water ?

The mole of fraction of NaCl in a solution containing 1 "mole" of NaCl "in" 100 g of water is:

The mole fraction of NaCl in a solution containing 1 mole of NaCl in 1000 g of water is

Calculate the mass fraction and mole fraction of ethyl alcohol and H_(2) O in a solution containing 9.2 g of alcohol in 18.0 g of H_(2) O .

The mole fraction of CH_(3)OH in an aqueous solution is 0.02 and its density is 0.994 g cm^(-3) . Determine its molarity and molality.