If `75.2%` of compound is carbon and the rest of the weight is hydrogen, the formula of the compound is

Options

A. `C_(3)H_(6)`
B. `C_(2)H_(2)`
C. `C_(2)H_(4)`
D. `CH_(4)`

Explanation

To determine the formula of the compound given that 75.2% of it is carbon and the rest is hydrogen, we can follow these steps:

### Step 1: Determine the percentage of hydrogen
Since 75.2% of the compound is carbon, we can find the percentage of hydrogen by subtracting the percentage of carbon from 100%.

\[ \text{Percentage of Hydrogen} = 100\% - 75.2\% = 24.8\% \]

### Step 2: Convert percentages to grams
Assuming we have a 100 g sample of the compound, the mass of carbon and hydrogen can be directly taken as their percentages:

- Mass of Carbon = 75.2 g
- Mass of Hydrogen = 24.8 g

### Step 3: Calculate the number of moles of each element
To find the number of moles, we will use the formula:

\[ \text{Number of moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} \]

- Molar mass of Carbon (C) = 12 g/mol
- Molar mass of Hydrogen (H) = 1 g/mol

Calculating the moles:

\[ \text{Moles of Carbon} = \frac{75.2 \text{ g}}{12 \text{ g/mol}} = 6.27 \text{ moles} \]

\[ \text{Moles of Hydrogen} = \frac{24.8 \text{ g}}{1 \text{ g/mol}} = 24.8 \text{ moles} \]

### Step 4: Find the simplest mole ratio
Next, we need to find the simplest whole number ratio of moles of carbon to moles of hydrogen. We can do this by dividing both by the smallest number of moles calculated:

\[ \text{Ratio of Carbon} = \frac{6.27}{6.27} = 1 \]

\[ \text{Ratio of Hydrogen} = \frac{24.8}{6.27} \approx 4 \]

### Step 5: Write the empirical formula
The simplest whole number ratio of carbon to hydrogen is 1:4. Therefore, the empirical formula of the compound is:

\[ \text{Empirical Formula} = \text{C}_1\text{H}_4 \text{ or simply } \text{CH}_4 \]

### Final Answer
The formula of the compound is **CH₄**.

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