Home
Class 11
CHEMISTRY
4.9 g of H(2)SO(4) is present in 100 mL ...

4.9 g of `H_(2)SO_(4)` is present in 100 mL of the solution. What is the molarity of the solution ? Calculate its normality also.

A

1, 0.5

B

1, 1

C

0.5, 1

D

0.5, 2

Text Solution

Verified by Experts

The correct Answer is:
C
`M=(w)/("GMW")xx(1000)/("V in ml")`
`N=Mxx"Basicity of an acid"`
Promotional Banner

Topper's Solved these Questions

  • SOME BASIC CONCEPTS OF CHEMISTRY

    NARAYNA|Exercise EXERCISE - III|31 Videos

  • SOME BASIC CONCEPTS OF CHEMISTRY

    NARAYNA|Exercise EXERCISE - IV|43 Videos

  • SOME BASIC CONCEPTS OF CHEMISTRY

    NARAYNA|Exercise EXERCISE - II (H.W)(NUMERICAL CALCULATIONS BASED ON CHEMICAL EQUATIONS)|11 Videos

  • SOME BASIC CONCEPTS IN CHEMISTRY STOICHIOMETRY (PART-I)

    NARAYNA|Exercise All Questions|555 Videos

  • SOME BASIC PRINCIPLES AND TECHNIQUES

    NARAYNA|Exercise EXERCISE -IV (QUALITATIVE AND QUANTITATIVE ANALYSIS OF ORGANIC OF COMPOUNDS)|8 Videos

Similar Questions

Explore conceptually related problems

6.8 g H_(2)O_(2) present in 100 mL of its solution. What is the molarity of solution?

0.8g of H_(2)SO_(4) is present in 2 litres of a solution. The molarity of the solution is

4.9 g of sulphuric acid is present in 500 mL of the solution. Calculate the pH of the solution.

18g of glucose (molar mass 180g "mol"^(-1) ) is present in 500CM^(3) of its aqueous solution. What is the molarity of the solution? What additional data is required if the molality of the solution is also required to be calculated?

If 36.0 g of glucose is present in 400 ml of solution, molarity of the solution is

If 0.56 g KOH is present in 100 mL of solution, then its normality will be