Which has maximum number of molecules among the following?

Options

A. `44gm CO_(2)`
B. `48gm O_(3)`
C. `8gm H_(2)`
D. `64gmSO_(2)`

Explanation

To determine which option has the maximum number of molecules, we need to calculate the number of moles for each substance given in the options and then convert those moles to molecules using Avogadro's number (6.022 x 10^23 molecules/mole).

### Step-by-Step Solution:

1. **Identify the options and their given weights:**
- Option 1: 44 g of CO2
- Option 2: 48 g of O3
- Option 3: 8 g of H2
- Option 4: 64 g of SO2

2. **Calculate the molar mass of each compound:**
- **CO2:**
- C: 12 g/mol
- O: 16 g/mol (2 O atoms = 32 g/mol)
- Molar mass of CO2 = 12 + 32 = 44 g/mol

- **O3:**
- O: 16 g/mol (3 O atoms = 48 g/mol)
- Molar mass of O3 = 48 g/mol

- **H2:**
- H: 1 g/mol (2 H atoms = 2 g/mol)
- Molar mass of H2 = 2 g/mol

- **SO2:**
- S: 32 g/mol
- O: 16 g/mol (2 O atoms = 32 g/mol)
- Molar mass of SO2 = 32 + 32 = 64 g/mol

3. **Calculate the number of moles for each option:**
- **Option 1 (CO2):**
- Number of moles = Given weight / Molar mass = 44 g / 44 g/mol = 1 mole

- **Option 2 (O3):**
- Number of moles = 48 g / 48 g/mol = 1 mole

- **Option 3 (H2):**
- Number of moles = 8 g / 2 g/mol = 4 moles

- **Option 4 (SO2):**
- Number of moles = 64 g / 64 g/mol = 1 mole

4. **Convert moles to molecules using Avogadro's number:**
- **Option 1 (CO2):**
- Molecules = 1 mole × 6.022 x 10^23 = 6.022 x 10^23 molecules

- **Option 2 (O3):**
- Molecules = 1 mole × 6.022 x 10^23 = 6.022 x 10^23 molecules

- **Option 3 (H2):**
- Molecules = 4 moles × 6.022 x 10^23 = 24.088 x 10^23 molecules

- **Option 4 (SO2):**
- Molecules = 1 mole × 6.022 x 10^23 = 6.022 x 10^23 molecules

5. **Compare the number of molecules:**
- Option 1: 6.022 x 10^23 molecules
- Option 2: 6.022 x 10^23 molecules
- Option 3: 24.088 x 10^23 molecules
- Option 4: 6.022 x 10^23 molecules

### Conclusion:
The option with the maximum number of molecules is **Option 3 (8 g of H2)**, which has 24.088 x 10^23 molecules.