In an experiment it is shown that `10 mL` of `0.05 M` solution of chloride required `10 mL` of `0.1 M` solution of `AgNO_(3)`, which of the following will be the formula of the chloride (X stands for the symbol of the element other than chlorine):

Options

A. `X_(2)Cl_(3)`
B. `XCl_(2)`
C. `XCl_(4)`
D. `X_(2)Cl`

Answer

B

Explanation

`"no of moles"-Mxx"V in lit"`
`"no of moles of "AgNO_(3)`
`=0.1xx10xx10^(-3)=10^(-3)" moles"`
no of moles of chloride
`=0.05xx10xx10^(-3)=0.5xx10^(-3)" moles"`
`"no of moles of "AgNO_(3)="no of moles of "AgCl`
`therefore" no of moles of "AgCl=10^(-3)" moles"`
`therefore" 1 mole of chloride has to produce 2 moles of "Cl^(-)" ions"`