What is the mass of the precipitate formed when 50 mL of 16.9% solution of `AgNO_(3)` is mixed with 50 mL of 5.8% NaCl solution?

Options

A. 3.5 gm
B. 7.0 gm
C. 14 gm
D. 28 gm

Answer

B

Explanation

`"No of moles of AgNO"_(3)=Mxx"V in lit"`
`=(16.9xx10)/(169)xx50xx10^(-3)=5xx10^(-2)`
`"no of moles of NaCl"=(5.8xx10)/(58)xx50xx10^(-3)`
`=5xx10^(-2)`
`AgNO_(3)+NaClrarrAgCl darr+NaNO_(3)`
`therefore" No of moles of AgCl"=5xx10^(-2)`
`"weight of AgCl "=nxx"G.M.Wt"`
`=5xx10^(-2)xx143.5="7.0 gms"`