When burnt in air, 14.0g mixture of carbon and sulphur gives a mixture of `CO_(2) and SO_(2)` in the volume ratio of `2:1`, volume being measured at the same conditions of temperature and pressure the number of moles of carbon in the mixture is

Options

A. 0.75
B. 0.5
C. 0.4
D. 0.25

Answer

B

Explanation

Let weight of C be x g, then S will be `(14-x)g`
`(x//12)/((14-x)//32)=(2)/(1)`
`therefore x=6g," moles of C"=(6)/(12)=0.5`