The oxide of a metal contains `60%` of the metal. What will be the percentage of bromine in the bromide of the metal, if the valency of the metal is the same is both the oxide and the bromide :

Options

A. `~~87`
B. `~~70`
C. `~~77`
D. `~~93`

Answer

A

Explanation

`"meq. Of metal = meq of oxygen"`
`(60)/(E)=(40)/(8)`
`therefore" "E=12`
Now meq. Of metal = meq. Of bromide
`(100-a)/(12)=(a)/(80)`
`therefore" "a~~87%`