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A hydrocarbon 'X' have 81% of carbon. Vo...

A hydrocarbon 'X' have `81%` of carbon. Volume of `CO_(2)` liberated at 298K and 76 cm of Hg when 0.55gm of 'x' undergoes combustion

A

0.90l

B

11.09l

C

1.89l

D

1.09l

Text Solution

Verified by Experts

The correct Answer is:
A
`100 g ---- rarr 81g`
`0.55g --------rarr 0.4455 g`
`12g rarr24.4658l (V=(nRT)/(P)=(1xx0.0821xx298)/(1))`
`0.4455 g rarr 0.908 l`
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