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3.92g of ferrous ammonium sulphate (FAS)...

`3.92g` of ferrous ammonium sulphate (FAS) react completely with `50 mlN//10KMnO_(4)` solution. The percentage purity of the sample is

A

50

B

78.4

C

80

D

28

Text Solution

Verified by Experts

The correct Answer is:
A
`"Eq of "KMnO_(4)" used"=(50xx1)/(1000xx10)=0.005`
`therefore" Eq of FAS reacted = 0.005"`
`therefore" Weight of FAS needed"`
`=0.005xx392=1.96g`
Thus percentage pure of FAS is `50%`
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