The `IE_1 " and " IE_2` of Mg (g) are 740 and `1450 kJ "mol:^(-1)` . Calculate the percentage of `Mg^(+)` (g) and `Mg^(2+)` (g) if 1g of Mg (g) absorbs 50 kJ of energy.

Options

A. `%Mg^(+)=50` and `%Mg^(+2)=50`
B. `%Mg^(+)=70.13` and `%Mg^(+2)=29.87`
C. `%Mg^(+)=75` and `% Mg^(+2)=25`
D. `%Mg^(+)=60` and `%Mg^(+2)=40`

Answer

B

Explanation

`Mg overset(740)rarr Mg^(+) overset(1540)rarr Mg^(+2)`
The amount of energy required for first step = 740 kJ remaing energy `= 1200-740=460` kJ
1540 kJ `to` mole
460 KJ `to ? = 29.87%`