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Hybrid orbital with least s- character i...

Hybrid orbital with least s- character is

A

`sp^3d`

B

`sp^2`

C

`sp^3`

D

sp

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To determine which hybrid orbital has the least s-character, we need to analyze the s-character of each given hybrid orbital: sp3d, sp2, sp3, and sp. Here’s a step-by-step breakdown: ### Step 1: Identify the Hybrid Orbitals The hybrid orbitals we need to analyze are: - sp3d - sp2 - sp3 - sp ### Step 2: Calculate the s-character for each hybrid orbital 1. **sp3d Hybridization:** - Participating orbitals: 1s + 3p + 1d = 5 orbitals - s-character = (Number of s orbitals / Total orbitals) × 100 - s-character = (1 / 5) × 100 = 20% 2. **sp2 Hybridization:** - Participating orbitals: 1s + 2p = 3 orbitals - s-character = (1 / 3) × 100 = 33.33% 3. **sp3 Hybridization:** - Participating orbitals: 1s + 3p = 4 orbitals - s-character = (1 / 4) × 100 = 25% 4. **sp Hybridization:** - Participating orbitals: 1s + 1p = 2 orbitals - s-character = (1 / 2) × 100 = 50% ### Step 3: Compare the s-character values Now we can summarize the s-character percentages for each hybrid orbital: - sp3d: 20% - sp2: 33.33% - sp3: 25% - sp: 50% ### Step 4: Determine the hybrid orbital with the least s-character From the calculated values, we can see that: - The hybrid orbital with the least s-character is **sp3d** with 20% s-character. ### Conclusion The hybrid orbital with the least s-character is **sp3d**. ---

To determine which hybrid orbital has the least s-character, we need to analyze the s-character of each given hybrid orbital: sp3d, sp2, sp3, and sp. Here’s a step-by-step breakdown: ### Step 1: Identify the Hybrid Orbitals The hybrid orbitals we need to analyze are: - sp3d - sp2 - sp3 - sp ...
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According to hybridisation theory, the % s-character in sp, sp^(2) and sp^(3) hybrid orbitals is 50, 33.3 and 25 respectively, but this is not true for all the species. When theta is the bond angle between equivalent hybrid orbitals then % s and p-character in hybrid orbitals (when only s and p-orbitals are involved in hybridisation) can be calculated by the following formula : costheta=(S)/(S-1)=(P-1)/(P) Q. Two elements X and Y combined together to form a covalent compound. If % p-character is found to be 80% in a orbital then the hybridised state of central atom X for the orbital is :