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Hybrid orbital with maximum p-character ...

Hybrid orbital with maximum p-character is

A

`sp^3d`

B

`sp^3`

C

`sp`

D

`sp^3d^2`

Text Solution

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The correct Answer is:
To determine which hybrid orbital has the maximum p-character, we will analyze the given hybrid orbitals: sp3d, sp3, sp, and sp3d2. We will calculate the percentage of p-character for each hybridization. ### Step 1: Analyze SP3D Hybridization - **Participating Orbitals**: 1s, 3p, and 1d = 5 orbitals - **P Orbitals**: 3 (from 3p) - **Percentage of P Character**: \[ \text{Percentage} = \left( \frac{\text{Number of p orbitals}}{\text{Total number of orbitals}} \right) \times 100 = \left( \frac{3}{5} \right) \times 100 = 60\% \] ### Step 2: Analyze SP3 Hybridization - **Participating Orbitals**: 1s and 3p = 4 orbitals - **P Orbitals**: 3 (from 3p) - **Percentage of P Character**: \[ \text{Percentage} = \left( \frac{3}{4} \right) \times 100 = 75\% \] ### Step 3: Analyze SP Hybridization - **Participating Orbitals**: 1s and 1p = 2 orbitals - **P Orbitals**: 1 (from 1p) - **Percentage of P Character**: \[ \text{Percentage} = \left( \frac{1}{2} \right) \times 100 = 50\% \] ### Step 4: Analyze SP3D2 Hybridization - **Participating Orbitals**: 1s, 3p, and 2d = 6 orbitals - **P Orbitals**: 3 (from 3p) - **Percentage of P Character**: \[ \text{Percentage} = \left( \frac{3}{6} \right) \times 100 = 50\% \] ### Step 5: Compare the Percentages - SP3D: 60% - SP3: 75% - SP: 50% - SP3D2: 50% ### Conclusion The hybrid orbital with the maximum p-character is **SP3**, which has 75% p-character. ### Final Answer **SP3 is the correct answer.** ---

To determine which hybrid orbital has the maximum p-character, we will analyze the given hybrid orbitals: sp3d, sp3, sp, and sp3d2. We will calculate the percentage of p-character for each hybridization. ### Step 1: Analyze SP3D Hybridization - **Participating Orbitals**: 1s, 3p, and 1d = 5 orbitals - **P Orbitals**: 3 (from 3p) - **Percentage of P Character**: \[ \text{Percentage} = \left( \frac{\text{Number of p orbitals}}{\text{Total number of orbitals}} \right) \times 100 = \left( \frac{3}{5} \right) \times 100 = 60\% ...
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