The number of sigma and Pi bonds in a molecule of cyanogen are

Options

A. 4,3
B. 3,4
C. 5,2
D. 3,5

Explanation

To determine the number of sigma and pi bonds in a molecule of cyanogen (C₂N₂), we can follow these steps:

### Step 1: Understand the Structure of Cyanogen
Cyanogen has the molecular formula C₂N₂. It consists of two carbon atoms and two nitrogen atoms. The structure can be represented as follows:

```
N≡C-C≡N
```

### Step 2: Identify the Types of Bonds
In the structure of cyanogen, each carbon (C) is connected to another carbon (C) and to a nitrogen (N) through a triple bond. Each triple bond consists of one sigma bond and two pi bonds.

### Step 3: Count the Sigma Bonds
1. **Between the two carbon atoms (C-C)**: There is **1 sigma bond**.
2. **Between each carbon and nitrogen (C≡N)**: Each C≡N bond has **1 sigma bond**. Since there are two such bonds (one for each carbon), that gives us **2 sigma bonds**.

So, the total number of sigma bonds in cyanogen is:
- 1 (C-C) + 2 (C≡N) = **3 sigma bonds**.

### Step 4: Count the Pi Bonds
1. **Between the two carbon atoms (C-C)**: There are **0 pi bonds** since it is a single bond.
2. **Between each carbon and nitrogen (C≡N)**: Each C≡N bond has **2 pi bonds**. Since there are two such bonds, that gives us **4 pi bonds**.

So, the total number of pi bonds in cyanogen is:
- 0 (C-C) + 4 (from two C≡N bonds) = **4 pi bonds**.

### Conclusion
In a molecule of cyanogen (C₂N₂), there are:
- **3 sigma bonds**
- **4 pi bonds**

### Final Answer
The number of sigma and pi bonds in cyanogen is **3 sigma bonds and 4 pi bonds**.

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