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A+B rarr C+D Initially moles of A and B ...

`A+B rarr C+D`
Initially moles of A and B are equal. At equilibrium, moles of C are three times of A. The equilibrium constant of the reaction will be

A

`P_(A) lt P_(B) & P_(D) lt P_(C)`

B

`P_(C)=2P_(D) & P_(A)=3P_(B)//4`

C

`P_(A)=P_(C) & P_(B)=P_(D)`

D

`P_(A) gt P_(D) & P_(A) gt P_(C)`

Text Solution

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The correct Answer is:
C
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